Botvinnik-Myasoedov, Leningrad Ch. 1930-31

Kasparov analyzes this game in MGP2: Houdini seems to have found a cool correction to his notes: the variation 24.Kb3!? also draws (Kasparov says it loses), and forces Black to find an amazing save.

You can play through on Chess Flash here. The PGN below is identical.


White to play

[Event “Leningrad-ch”]
[Site “Leningrad”]
[Date “1930.??.??”]
[Round “?”]
[White “Botvinnik, Mikhail”]
[Black “Myasoyedov, G.”]
[Result “1/2-1/2”]
[ECO “E23”]
[Annotator “MGP 2.31”]
[PlyCount “60”]
[EventDate “1930.??.??”]
[EventType “tourn”]
[EventRounds “16”]
[EventCountry “URS”]
[Source “ChessBase”]
[SourceDate “1998.11.10”]

  1. d4 Nf6 2. c4 e6 3. Nc3 Bb4 4. Qb3 c5 5. dxc5 Nc6 6. Nf3 Ne4 7. Bd2 Nxc5 8.
    Qc2 f5 9. a3 Bxc3 10. Bxc3 O-O 11. b4 Ne4 12. Bb2 b6 13. g4 Nxf2 $1 14. Kxf2
    fxg4 15. Rg1 Qh4+ 16. Ke3 Qh6+ 17. Kf2 Qh4+ 18. Ke3 Qh6+ 19. Kd3 d5 $1 20. Qc1
    $1 dxc4+ $1 (20… Rf4 $1 21. Ne5 $1 (21. Nd2 e5 22. Kc3 Rf2 23. Ne4 Qxc1+ 24.
    Rxc1 dxe4 $17) (21. Kc2 Rxc4+ 22. Bc3 Qf6 23. Kb3 e5 $1) 21… Bb7 $15) 21.
    Qxc4 Rd8+ 22. Kc2 Bb7 23. Qxg4 Nxb4+ $1 24. axb4 (24. Qxb4 Rac8+ 25. Bc3 Bxf3
  2. Rd1 (26. exf3 a5) 26… Rxc3+ 27. Qxc3 Be4+ 28. Rd3 Rxd3 29. exd3 Qxh2+ 30.
    Bg2 Bxg2 {(Botvinnik)} 31. Qc8+ Kf7 32. Qd7+ Kf8 33. Qd8+ $11 {(Kasparov)}) ({
    Kasparov" "But doesn’t} 24. Kb3 {win?–after all, in the event of} Qe3+ {(?)}
  3. Bc3 Bd5+ 26. Kb2 {“Black’s attack peters out” (Kasparov)}) (24. Kb3 {
    Kasparov: “But as soon as Fritz is switched on, it all becomes clear”} Bd5+ $1
  4. Kxb4 g6 $3 {“and White is completely defenceless!” (Kasparov)} {But doesn’t
    } 26. Qg5 $1 {draw?} {Black has a beautiful perpetual after} Rac8 (26… Qf8+
  5. Kc3 Bxf3 28. exf3 Qxf3+ (28… Rac8+ 29. Kb3) 29. Kc2 Rd5 30. Qg3) (26…
    a5+ 27. Kc3 Rac8+ 28. Kd2 Bxf3+ 29. Ke3 {and White seems to have lived.}) 27.
    Qxh6 Rc4+ 28. Kb5 Rc5+ 29. Kb4 (29. Ka6 $4 Ra5#) 29… Rc4+ 30. Kb3 Rcc8+ 31.
    Ka4 Rc4+ $11) 24… Rac8+ 25. Bc3 Rxc3+ 26. Kxc3 Qe3+ 27. Kb2 Rd2+ 28. Nxd2
    Qxd2+ 29. Kb1 Qd1+ 30. Kb2 Qd2+ 1/2-1/2